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25q^2+15q+1=5q
We move all terms to the left:
25q^2+15q+1-(5q)=0
We add all the numbers together, and all the variables
25q^2+10q+1=0
a = 25; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·25·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$q=\frac{-b}{2a}=\frac{-10}{50}=-1/5$
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